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0=4x^2+12x+10x+120
We move all terms to the left:
0-(4x^2+12x+10x+120)=0
We add all the numbers together, and all the variables
-(4x^2+12x+10x+120)=0
We get rid of parentheses
-4x^2-12x-10x-120=0
We add all the numbers together, and all the variables
-4x^2-22x-120=0
a = -4; b = -22; c = -120;
Δ = b2-4ac
Δ = -222-4·(-4)·(-120)
Δ = -1436
Delta is less than zero, so there is no solution for the equation
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